[R-lang] Poisson MLR

[Stefan Th. Gries]

Hm, can't you compare the difference of the null and the residual
deviances against a chi-square distribution with
df=df_nulldev-df_resdev? (Just like when you use anova(model1, model2,
test="Chi") during model simplification?)
HTH,
STG
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Stefan Th. Gries
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University of California, Santa Barbara
http://www.linguistics.ucsb.edu/faculty/stgries
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