[R-lang] Plotting CI from Mixed Effects Model
Corey McMillan
Corey.McMillan at ed.ac.uk
Fri Sep 21 09:26:47 PDT 2007
Hi-
I am reporting results from a mixed effects model in which Place (-,+) and
Voice (-,+) are fixed effect factors. I would like to plot the coefficient
estimates along with their 95% CIs to visualise my results. The model and
MCMC estimations look like this:
artic.lmer <- lmer(nonorm ~ relevel(artic5$place, "place-") *
relevel(voice, "voice-") + (1 | sub) + (1 | item), data=artic5)
pvals.fnc(artic.lmer)
$fixed
Estimate
(Intercept) 1.7156
relevel(artic5$place, "place-")place+ 1.4482
relevel(voice, "voice-")voice+ 0.9149
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ -1.0889
MCMCmean
(Intercept) 1.7169
relevel(artic5$place, "place-")place+ 1.4504
relevel(voice, "voice-")voice+ 0.9147
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ -1.0918
HPD95lower
(Intercept) 1.0303
relevel(artic5$place, "place-")place+ 0.9469
relevel(voice, "voice-")voice+ 0.3433
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ -1.6631
HPD95upper
(Intercept) 2.4780
relevel(artic5$place, "place-")place+ 1.9432
relevel(voice, "voice-")voice+ 1.4374
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ -0.4564
pMCMC
(Intercept) 0.0012
relevel(artic5$place, "place-")place+ 0.0001
relevel(voice, "voice-")voice+ 0.0012
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ 0.0006
Pr(>|t|)
(Intercept) 0.0000
relevel(artic5$place, "place-")place+ 0.0000
relevel(voice, "voice-")voice+ 0.0009
relevel(artic5$place, "place-")place+:relevel(voice, "voice-")voice+ 0.0004
My understanding is that the value for each cell in the 2 X 2 design can be
calculated in the following way:
place-,voice- = 1.7156
place-,voice+ = 1.7516 + 0.9149 = 2.67
place+, voice- = 1.7516 + 1.4482 = 3.20
place+,voice+ = 1.7516 + 0.9149 + 1.4482 - 1.0889 = 3.03
Now if I want to report the 95% CIs around those values can I use the same
procedure? So the place-,voice+ lower CI would be equivalent to 0.9469 +
1.7156 and the higher CI equivalent to 1.943 + 1.7156, and so on...
Any clarifications on this would be greatly appreciated.
Cheers,
Corey McMillan
--
Corey McMillan
University of Edinburgh
School of Philosophy, Psychology, and Language Sciences
email: Corey.McMillan at ed.ac.uk
web: http://homepages.ed.ac.uk/s0340151
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