In problem 3, I have a perfectly good plot (using plot()) of the function that seems to estimate the histogram. However, I am really having problems using lines() to overlay it on top of the histogram. It just keeps saying:
<br><br>Error in as.vector(x, "double") : cannot coerce to vector<br><br>So I guess my function isn't in vector format... but I can't figure out how to make it one. In Baayen pg. 27 I think he's answering this question but I can't follow what he's saying.
<br>Any tips?<br>Kate<br><br><div><span class="gmail_quote">On 10/21/07, <b class="gmail_sendername"><a href="mailto:rlevy@ling.ucsd.edu">rlevy@ling.ucsd.edu</a></b> <<a href="mailto:rlevy@ling.ucsd.edu">rlevy@ling.ucsd.edu
</a>> wrote:</span><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">Rebecca Colavin wrote:<br>> Okay, I give up.<br>><br>> The graph in the question generates a distribution where the probability
<br><br>> mass (=1) is contained under the curve. In short, the y axis is (0,9) or<br><br>> so .<br>><br>> But when I try to do lines over it with a normal distribution, the y<br>values are probabilities. The y axis for this is (0,1).
<br><br>Hi Rebecca,<br><br>Because the normal distribution is a continuous probability density, the<br>y values (for the density) are not bounded above by 1. Remember, it is<br>the *area under the curve* that must total 1. If the scale of the x axis
<br>is small, p(x) can easily surpass 1.<br><br>As an example, try:<br><br> > x <- seq(-5,5,by=0.01)<br> > plot(x,dnorm(x,0,0.1),type="l")<br><br>This normal density peaks around p(x) = 4.<br><br>Using hist() with prob=T also is an estimation of density, which is why
<br>the hist() y axis also surpasses 1.<br><br><br>Roger<br><br><br>--<br><br>Roger Levy Email: <a href="mailto:rlevy@ucsd.edu">rlevy@ucsd.edu</a><br>Assistant Professor Phone: 858-534-7219
<br>Department of Linguistics Fax: 858-534-4789<br>UC San Diego Web: <a href="http://ling.ucsd.edu/~rlevy">http://ling.ucsd.edu/~rlevy</a><br><br><br><br><br><br>_______________________________________________
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